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Lutein-13C40 PubChem CID 131708939
[13CH3][13C]1=[13CH][13C@H](O)[13CH2][13C]([13CH3])([13CH3])[13C@H]1/[13CH]=[13CH]/[13C]([13CH3])=[13CH]/[13CH]=[13CH]/[13C]([13CH3])=[13CH]/[13CH]=[13CH]/[13CH]=[13C]([13CH3])/[13CH]=[13CH]/[13CH]=[13C]([13CH3])/[13CH]=[13CH]/[13C]1=[13C]([13CH3])[13CH2][13C@@H](O)[13CH2][13C]1([13CH3])[13CH3]