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CCCCCCCCCCCC=N[N+](C)(C)C.[I-] -
CCCCCCCCCCC/C=N\[N+](C)(C)C.[I-]
Powered by a PubChem CID-based index. Search by name, synonym, CAS number, or SMILES.
CCCCCCCCCCCC=N[N+](C)(C)C.[I-]
CCCCCCCCCCC/C=N\[N+](C)(C)C.[I-]