Compound Search
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基于 PubChem CID 索引,支持名称 / 同义词 / CAS / SMILES 检索。
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4,6(1H,5H)-Pyrimidinedione, dihydro-5-((4-methoxyphenyl)methylene)-2-thioxo- CAS 60045-61-6 PubChem CID 677067
COc1ccc(C=C2C(=O)NC(=S)NC2=O)cc1 -
5-[(Z,2E)-3-(4-methoxyphenyl)-2-propenylidene]-2-thioxodihydro-1H-imidazol-4-one CAS 420105-41-5 PubChem CID 703355
COc1ccc(C=CC=C2NC(=S)NC2=O)cc1 -
4,6(1H,5H)-Pyrimidinedione, 5-[(3,4-dimethoxyphenyl)methylene]dihydro-2-thioxo- CAS 60045-60-5 PubChem CID 727451
COc1ccc(C=C2C(=O)NC(=S)NC2=O)cc1OC -
5-cinnamylidene-1-prop-2-enyl-1,3-diazinane-2,4,6-trione PubChem CID 800789
C=CCN1C(=O)NC(=O)C(=CC=Cc2ccccc2)C1=O -
1-(3-chlorophenyl)-5-cinnamylidene-1,3-diazinane-2,4,6-trione PubChem CID 1346988
O=C1NC(=O)N(c2cccc(Cl)c2)C(=O)C1=CC=Cc1ccccc1 -
1-(3-methoxyphenyl)-5-[3-(2-nitrophenyl)prop-2-enylidene]-1,3-diazinane-2,4,6-trione PubChem CID 1353493
COc1cccc(N2C(=O)NC(=O)C(=CC=Cc3ccccc3[N+](=O)[O-])C2=O)c1 -
1-(3-bromophenyl)-5-cinnamylidene-1,3-diazinane-2,4,6-trione PubChem CID 1360731
O=C1NC(=O)N(c2cccc(Br)c2)C(=O)C1=CC=Cc1ccccc1 -
1-benzyl-5-cinnamylidene-1,3-diazinane-2,4,6-trione PubChem CID 1375951
O=C1NC(=O)N(Cc2ccccc2)C(=O)C1=CC=Cc1ccccc1 -
(5Z)-5-[(2E)-3-(4-METHOXYPHENYL)PROP-2-EN-1-YLIDENE]-2-SULFANYLIDENEIMIDAZOLIDIN-4-ONE PubChem CID 2057001
COc1ccc(/C=C/C=C2\NC(=S)NC2=O)cc1 -
(5E)-1-(3-bromophenyl)-5-[(2E)-3-phenylprop-2-en-1-ylidene]pyrimidine-2,4,6(1H,3H,5H)-trione PubChem CID 2258395
O=C1NC(=O)N(c2cccc(Br)c2)C(=O)/C1=C/C=C/c1ccccc1 -
(5E)-1-benzyl-5-[(E)-3-phenylprop-2-enylidene]-1,3-diazinane-2,4,6-trione PubChem CID 2288294
O=C1NC(=O)N(Cc2ccccc2)C(=O)/C1=C/C=C/c1ccccc1 -
(5E)-5-[(E)-3-phenylprop-2-enylidene]-1-prop-2-enyl-1,3-diazinane-2,4,6-trione PubChem CID 2293359
C=CCN1C(=O)NC(=O)/C(=C\C=C\c2ccccc2)C1=O -
5-((2E)-3-phenylprop-2-enylidene)-1-(3-chlorophenyl)-1,3-dihydropyrimidine-2,4 ,6-trione PubChem CID 5507642
O=C1NC(=O)N(c2cccc(Cl)c2)C(=O)/C1=C/C=C/c1ccccc1 -
(E)-1-(3-methoxyphenyl)-5-((E)-3-(2-nitrophenyl)allylidene)pyrimidine-2,4,6(1H,3H,5H)-trione PubChem CID 5508448
COc1cccc(N2C(=O)NC(=O)/C(=C\C=C\c3ccccc3[N+](=O)[O-])C2=O)c1