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基于 PubChem CID 索引，支持名称 / 同义词 / CAS / SMILES 检索。
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copper(2+) 2,11,20,29,37,38,39,40-octaazanonacyclo[28.6.1.1(3),(1)?.1(1)(2),(1)?.1(2)(1),(2)?.0?,?.0(1)(3),(1)?.0(2)(2),(2)?.0(3)(1),(3)?]tetraconta-1(36),2,4(9),5,7,10(40),11,13(18),14,16,19(39),20,22(27),23,25,28,30,32,34-nonadecaene-37,38-diide CAS 147-14-8 PubChem CID 6531516
[Cu+2].c1ccc2c(c1)-c1nc-2nc2[n-]c(nc3nc(nc4[n-]c(n1)c1ccccc41)-c1ccccc1-3)c1ccccc21 -
Sodium (Z)-(3aR,4R,5R,6aS)-hexahydro-5-hydroxy-4-((E)-(3S)-3-hydroxy-1-octenyl)-2H-cyclopenta(b)furan-delta(sup 2,delta)-valerate CAS 61849-14-7 PubChem CID 159
CCCCCC(O)C=CC1C(O)CC2OC(=CCCCC(=O)O)CC21 -
CCCCCCC(CCCCCCCCCCC(=O)O)OC(C)CO -
(1R)-2-{[{[(2S)-2,3-DIHYDROXYPROPYL]OXY}(HYDROXY)PHOSPHORYL]OXY}-1-[(PALMITOYLOXY)METHYL]ETHYL (11E)-OCTADEC-11-ENOATE PubChem CID 134737986
CCCCCC/C=C/CCCCCCCCCC(=O)O[C@H](COC(=O)CCCCCCCCCCCC)COP(=O)(O)OC[C@@H](O)CO -
1-hentriacontanoyl-2-acetyl-sn-glycero-3-phospho-(1'-sn-glycerol) PubChem CID 145718872
CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC(=O)OC[C@H](COP(=O)(O)OC[C@@H](O)CO)OC(C)=O -
1-hentriacontanoyl-2-butyryl-sn-glycero-3-phospho-(1'-sn-glycerol) PubChem CID 145718874
CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC(=O)OC[C@H](COP(=O)(O)OC[C@@H](O)CO)OC(=O)CCC -
1-tetradecyl-2-hentriacontanoyl-sn-glycero-3-phospho-(1'-sn-glycerol) PubChem CID 145718921
CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC(=O)O[C@H](COCCCCCCCCCCCCCC)COP(=O)(O)OC[C@@H](O)CO -
1-hexadecyl-2-hentriacontanoyl-sn-glycero-3-phospho-(1'-sn-glycerol) PubChem CID 145718942
CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC(=O)O[C@H](COCCCCCCCCCCCCCCCC)COP(=O)(O)OC[C@@H](O)CO -
1-octadecyl-2-hentriacontanoyl-sn-glycero-3-phospho-(1'-sn-glycerol) PubChem CID 145718963
CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC(=O)O[C@H](COCCCCCCCCCCCCCCCCCC)COP(=O)(O)OC[C@@H](O)CO -
1-eicosyl-2-hentriacontanoyl-sn-glycero-3-phospho-(1'-sn-glycerol) PubChem CID 145718984
CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC(=O)O[C@H](COCCCCCCCCCCCCCCCCCCCC)COP(=O)(O)OC[C@@H](O)CO -
1-docosyl-2-hentriacontanoyl-sn-glycero-3-phospho-(1'-sn-glycerol) PubChem CID 145719016
CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC(=O)O[C@H](COCCCCCCCCCCCCCCCCCCCCCC)COP(=O)(O)OC[C@@H](O)CO