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基于 PubChem CID 索引，支持名称 / 同义词 / CAS / SMILES 检索。
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[5,10,15,20-tetrakis(pentafluorophenyl)porphyrinato-kappa(4)N(21),N(22),N(23),N(24)]platinum(II) CAS 109781-47-7 PubChem CID 5190808
Fc1c(F)c(F)c(-c2c3nc(c(-c4c(F)c(F)c(F)c(F)c4F)c4ccc([n-]4)c(-c4c(F)c(F)c(F)c(F)c4F)c4nc(c(-c5c(F)c(F)c(F)c(F)c5F)c5ccc2[n-]5)C=C4)C=C3)c(F)c1F.[Pt+2] -
platinum(2+) 2,7,12,17-tetrakis(2,3,4,5,6-pentafluorophenyl)-21,22,23,24-tetraazapentacyclo[16.2.1.1(3),?.1?,(1)(1).1(1)(3),(1)?]tetracosa-1(21),3(24),4,6,8(23),10,12,14,16(22),17,19-undecaene-2,9-diide CAS 109781-47-7 PubChem CID 6535910
Fc1c(F)c(F)c(C2=C3C=CC(=N3)[C-](c3c(F)c(F)c(F)c(F)c3F)C3=NC(=C(c4c(F)c(F)c(F)c(F)c4F)c4[cH-]cc(n4)C(c4c(F)c(F)c(F)c(F)c4F)=C4C=CC2=N4)C=C3)c(F)c1F.[Pt+2] -
(1Z,6Z,12Z,17Z)-2,7,12,17-tetrakis(2,3,4,5,6-pentafluorophenyl)-21,23,24,25-tetraaza-22-platinahexacyclo[9.9.3.1(3),?.1(1)(3),(1)?.0?,(2)(3).0(1)?,(2)(1)]pentacosa-1,3(25),4,6,8,10,12,14,16(24),17,19-undecaene CAS 109781-47-7 PubChem CID 15174007
Fc1c(F)c(F)c(-c2c3nc(c(-c4c(F)c(F)c(F)c(F)c4F)c4ccc([n-]4)c(-c4c(F)c(F)c(F)c(F)c4F)c4nc(c(-c5c(F)c(F)c(F)c(F)c5F)c5ccc2[n-]5)C=C4)C=C3)c(F)c1F.[Pt+2] -
Fc1c(F)c(F)c(C2=C3CCC([N-]3)C(c3c(F)c(F)c(F)c(F)c3F)=c3ccc([n-]3)=C(c3c(F)c(F)c(F)c(F)c3F)C3CCC(=C(c4c(F)c(F)c(F)c(F)c4F)c4ccc2[n-]4)[N-]3)c(F)c1F.[Pt+4] -
5,10,15,20-Tetrakis(pentafluorophenyl)-21h,23h-porphine, platinum(ii) CAS 109781-47-7 PubChem CID 156595062
Fc1c(F)c(F)c(/C2=C3\CCC([N-]3)/C(c3c(F)c(F)c(F)c(F)c3F)=c3/cc/c([n-]3)=C(\c3c(F)c(F)c(F)c(F)c3F)C3CC/C(=C(\c4c(F)c(F)c(F)c(F)c4F)c4ccc2[n-]4)[N-]3)c(F)c1F.[Pt+4] -
5,10,15,20-Tetrakis(pentafluorophenyl)-21h,23h-porphine, platinum(ii) CAS 109781-47-7 PubChem CID 164886151
Fc1c(F)c(F)c(C2c3ccc([n-]3)C(c3c(F)c(F)c(F)c(F)c3F)C3C=CC(N3)C(c3c(F)c(F)c(F)c(F)c3F)c3ccc([n-]3)C(c3c(F)c(F)c(F)c(F)c3F)C3C=CC2N3)c(F)c1F.[Pt+2] -
Platinum,[5,10,15,20-tetrakis(pentafluorophenyl)-21H,23H-porphinato(2-)-kN21,kN22,kN23,kN24]-, (SP-4-1)- CAS 109781-47-7 PubChem CID 172878389
Fc1c(F)c(F)c(-c2c3nc(c(-c4c(F)c(F)c(F)c(F)c4F)c4ccc([n-]4)c(-c4c(F)c(F)c(F)c(F)c4F)c4nc(c(-c5c(F)c(F)c(F)c(F)c5F)c5ccc2=5)C=C4)C=C3)c(F)c1F.[Pt]